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Commit
c01eefd1
authored
3 years ago
by
BellCodeEditor
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38c1584f
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my_Tetris.py
my_Tetris.py
View file @
c01eefd1
...
@@ -6,7 +6,7 @@ score = 0
...
@@ -6,7 +6,7 @@ score = 0
grid_size
=
20
# 格子大小
grid_size
=
20
# 格子大小
grid_num_width
=
15
# 横向格子数量
grid_num_width
=
15
# 横向格子数量
grid_num_height
=
25
# 纵向格子数量
grid_num_height
=
25
# 纵向格子数量
FPS
=
111111
FPS
=
30
# 创建窗口
# 创建窗口
screen
=
pygame
.
display
.
set_mode
((
460
,
500
))
screen
=
pygame
.
display
.
set_mode
((
460
,
500
))
...
@@ -34,9 +34,9 @@ while True:
...
@@ -34,9 +34,9 @@ while True:
# 将背景图画上去
# 将背景图画上去
screen
.
blit
(
background
,(
0
,
0
))
screen
.
blit
(
background
,(
0
,
0
))
pygame
.
draw
.
rect
(
screen
,(
194
,
34
,
134
),(
center
[
1
]
*
20
-
20
,
center
[
0
]
*
20
-
20
,
20
,
20
),
0
)
pygame
.
draw
.
rect
(
screen
,(
194
,
34
,
134
),(
center
[
1
]
*
20
-
20
,
center
[
0
]
*
20
-
20
,
20
,
20
),
0
)
#***center[1]*20-20*
**表示他格子的列乘他的格子数因为是从左上角开始渲染所以要减20,_____center[0]*20-20__
__表示格子所在的行乘他的格子数因为是从左上角开始渲染所以要减20。得出来位置。
#***center[1]*20-20*
是x坐标**表示他格子的列乘他的格子数因为是从左上角开始渲染所以要减20,_____center[0]*20-20__是y坐标
__表示格子所在的行乘他的格子数因为是从左上角开始渲染所以要减20。得出来位置。
pygame
.
draw
.
rect
(
screen
,(
25
,
223
,
255
),(
center
[
1
]
*
20
-
20
,
center
[
0
]
*
20
-
20
,
20
,
20
),
1
)
pygame
.
draw
.
rect
(
screen
,(
25
,
223
,
255
),(
center
[
1
]
*
20
-
20
,
center
[
0
]
*
20
-
20
,
20
,
20
),
1
)
#***center[1]*20-20*
**表示边框所在的列乘他的格子数因为是从左上角开始渲染所以要减20,___center[0]*20-20__
_表示边框所在的行乘他的格子数因为是从左上角开始渲染所以要减20。得出来位置。
#***center[1]*20-20*
是x坐标**表示边框所在的列乘他的格子数因为是从左上角开始渲染所以要减20,___center[0]*20-20__是y坐标
_表示边框所在的行乘他的格子数因为是从左上角开始渲染所以要减20。得出来位置。
# 得分
# 得分
score_text
=
font
.
render
(
str
(
score
),
True
,(
0
,
0
,
0
))
score_text
=
font
.
render
(
str
(
score
),
True
,(
0
,
0
,
0
))
screen
.
blit
(
score_text
,(
360
,
70
))
screen
.
blit
(
score_text
,(
360
,
70
))
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