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binary_search.py

 # 使用二分查找法，找出9和20在列表里面的索引
-num_list = [1, 3, 5, 8, 11, 15, 17, 18, 20, 21]
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+num_list = [1, 3, 5, 8, 11, 15, 17, 18, 20, 21]
+low=0
+hight=len(num_list)-1
+m=(low+hight)//2
+def a(low,hight,m):
+    num_list = [1, 3, 5, 8, 11, 15, 17, 18, 20, 21]
+    if num_list(m) == 20:
+        return m
+    else:
+        if num_list(m)>20:
+            return a(low,m-1,(low+m-1)//2)
+        else:
+            return a(m+1,hight,(m+1+hight)//2)
+print(a(low,hight,m))
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