save project

binary_search.py

 # 使用二分查找法，找出9和20在列表里面的索引
-num_list = [1, 3, 5, 8, 11, 15, 17, 18, 20, 21]
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+num_list = [1, 3, 5, 8, 11, 15, 17, 18, 20, 21]
+low = 0
+high = len(num_list) - 1
+n = 0 
+while True:
+    n = n + 1
+    mid = (low + high) // 2
+    if num_list[mid] ==20:
+        print("快速!,用了" + str(n) + "次")
+        break
+    elif num_list[mid] < 20:
+        low = mid + 1
+    else:
+        high = mid + 1
+    if high < low:
+        print("废物！,用了" + str(n) + "次")
+        break
+        
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