Commit 8616a667 by BellCodeEditor

auto save

parent 2db0ac81
Showing with 23 additions and 39 deletions
''' '''
#猴子吃桃子 #猴子吃桃
def pench(n): def p(d):
if n==10: #出口
if d==10:
return 1 return 1
num = (pench(n+1)+1)*2 n = (p(d+1)+1)*2
return num return n
peach_num = pench(7) res = p(6)
print(peach_num) print(res)
#请用递归实现1+2+3....+num的累加和 #实现1+2+3+...+num的累加和
#出口1 #出口 1
def sum_num(number): def s_n(n):
if number == 1: if n==1:
return 1 return 1
sum_temp = sum_num(number-1) temp = s_n(n-1)
return number+sum_temp v = n+temp
res = sum_num(3) return v
res = s_n(3)
print(res) print(res)
#求阶乘 5! 5!= 5*4*3*2*1
#兔子数量 #兔子数量
def f(n): def f(n):
if n<=2: if n<=2:
return 1 return 1
v = f(n-1)+f(n-2) v = f(n-1)+f(n-2)
return v return v
# elif n>2: r = f(20)
# v = f(n-1)+f(n-2) print(r)
# return v
res = f(6)
print(res)
#汉诺塔
def hlt(n):
if n==1:
return 1
count = 2*hlt(n-1)+1
return count
res = hlt(3)
print(res)
''' '''
#求阶乘 5! 5!= 5*4*3*2*1 #求阶乘 5! = 5*4*3*2*1
def f(x): def f(x):
if x==0: if x==0:
return 0 return 0
elif x==1: elif x==1:
return 1 return 1
else: else:
y = x*f(x-1) y = x * f(x-1)
return y return y
print(f(5)) r = f(5)
print(r)
Markdown is supported
0% or
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or sign in to comment