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lesson8-5
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Commit
0680bded
authored
2 years ago
by
BellCodeEditor
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diy.py
diy.py
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0680bded
# 持家小能手 (利用自动更新成绩程序的逻辑完成这个新项目)
# 如果输入的水果价钱比字典中的低,则替换掉,反之则不更新
cost
=
{
'苹果'
:
5.2
,
'山竹'
:
12.9
,
'香蕉'
:
2.4
,
'荔枝'
:
15
,
'葡萄'
:
9.3
,
'桂圆'
:
8
,
'蓝莓'
:
10
,
'李子'
:
8
}
k
=
input
(
'请输入水果名称:'
)
v
=
input
(
'请输入水果价钱:'
)
# ?补充条件判断:
if
# ?:
# ?更新价钱
print
(
k
+
'降价了,现价'
+
v
+
'元'
)
else
:
print
(
k
+
'涨价了,我们不买'
)
else
:
cost
[
k
]
=
float
(
v
)
print
(
k
+
'的价钱'
+
v
+
'元已上传~'
)
# cost= {'苹果':5.2,'山竹':12.9,'香蕉':2.4,'荔枝':15,'葡萄':9.3,'桂圆':8,'蓝莓':10,'李子':8}
# k=input('请输入水果名称:')
# v=input('请输入水果价钱:')
# # ?补充条件判断:
# if k in cost:
# if int(v)<cost[k]:
# # ?更新价钱
# print(k+'降价了,现价'+v+'元')
# else:
# print(k+'涨价了,我们不买')
# else:
# cost[k] = float(v)
# print(k+'的价钱'+v+'元已上传~')
import
random
# 私钥
key
=
"abcdefgh使用python实现简单的位移替换加密,制作密码机关真是太好玩了哈哈哈!"
# 要加密语句
message
=
input
(
"请输入:"
)
# 最终加密后的语句
d
=
""
# 干扰字符
noise
=
"port:@#$
%
^&"
for
i
in
message
:
str1
=
i
str2
=
random
.
choice
(
key
)
str3
=
random
.
choice
(
key
)
text
=
str1
+
str2
+
str3
d
=
d
+
text
a
=
list
(
d
)
c
=
random
.
randint
(
0
,
len
(
d
))
a
.
insert
(
5
,
noise
)
b
=
""
.
join
(
a
)
print
(
b
)
\ No newline at end of file
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