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Commit
0e2b9c4d
authored
Feb 08, 2022
by
BellCodeEditor
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parent
1d161ee1
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35 additions
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4 deletions
my_Tetris.py
my_Tetris.py
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0e2b9c4d
...
...
@@ -15,16 +15,47 @@ clock = pygame.time.Clock() # pygame时钟,控制游戏速度(帧数)
# 载入素材
background
=
pygame
.
image
.
load
(
'bg.png'
)
font
=
pygame
.
font
.
Font
(
'STKAITI.TTF'
,
60
)
# 字体
#创建一个列表记录方块的行与列
center
=
[
2
,
8
]
curr_shape
=
[(
0
,
-
1
),(
0
,
0
),(
0
,
1
),(
-
1
,
0
)]
while
True
:
for
event
in
pygame
.
event
.
get
():
if
event
.
type
==
locals
.
QUIT
:
exit
()
#是否按下键盘按键
if
event
.
type
==
locals
.
KEYDOWN
:
#按下右移键
if
event
.
key
==
locals
.
K_RIGHT
:
if
center
[
1
]
<
15
:
center
[
1
]
+=
1
#按下左移键
elif
event
.
key
==
locals
.
K_LEFT
:
if
center
[
1
]
>
1
:
center
[
1
]
-=
1
#按下下移键
elif
event
.
key
==
locals
.
K_DOWN
:
if
center
[
0
]
<
25
:
center
[
0
]
+=
1
# 将背景图画上去
???
screen
.
blit
(
background
,(
0
,
0
))
#创建一个空列表curr_pos
curr_pos
=
[]
#对记录方块行列的列表进行遍历
for
cube
in
curr_shape
:
#用相对位置加上屏幕中心点所在的位置
pos
=
(
cube
[
0
]
+
center
[
0
],
cube
[
1
]
+
center
[
1
])
#新得到的位置添加在我们空列表中
curr_pos
.
append
(
pos
)
#画出红色白边的小方块
#使用遍历方法把方块的每个小方块的行列取出
for
cube
in
curr_pos
:
pygame
.
draw
.
rect
(
screen
,(
255
,
0
,
0
),(
cube
[
1
]
*
20
-
20
,
cube
[
0
]
*
20
-
20
,
20
,
20
),
0
)
pygame
.
draw
.
rect
(
screen
,(
255
,
255
,
255
),(
cube
[
1
]
*
20
-
20
,
cube
[
0
]
*
20
-
20
,
20
,
20
),
1
)
# 得分
???
score_text
=
font
.
render
(
str
(
score
),
True
,(
0
,
0
,
0
))
screen
.
blit
(
score_text
,(
350
,
70
))
# 刷新画面
pygame
.
display
.
update
()
clock
.
tick
(
FPS
)
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