Commit 4e9e96f4 by BellCodeEditor

auto save

parent 828ed1b1
Showing with 258 additions and 5 deletions
# def a(x,y,z):
# print(x,y,z)
# a(2,3,4)#位置实参
# a(x=3,y=4,z=5)#关键字实参
# a(4,y=5,z=6)
# a(4,5,z=6)
# a(x=4,5,z=6)
# a(x=4,y=5,6)
# def a(y,x=1):
# print(x,y)
# a(3,2)
# my=lambda a,b=3: a*b
# print(my(4,3))
# def c(a,b):
# return a*b
# print(c(2,3))
# def a():
# print(1)
# a()
# def demo(n):
# return n*2
# print(demo(demo(demo(1))))
# x=1
# def demo():
# global x
# x=2
# print(x)
# demo()
# print(x)
# def f(s):
# t=0
# max=0
# for i in s:
# if i>='0' and i<='9':
# t+=1
# else:
# if t>max:
# max=t
# t=0
# print(max)
# list='2134abc47895cd6d'
# f(list)
# def a(n):
# if n==1:
# return 1
# s=a(n-1)+n
# return s
# print(a(100))
# a=[1,2,31,2,1]
# b=[]
# for i in a:
# b.insert(-1,i)
# print(b)
a=[i for i in range(10)]
print(a)
\ No newline at end of file
# def a(a,b,c):
# print('123'+str(a)+str(b)+str(c))
# a(3,2,1)#位置实参
# a(a=4,b=3,c=2)#关键字实参
# a(4,b=4,c=4)
# a(5,5,c=5)
#形参实参
# def a(x,y=2):
# print(x,y)
# a(1,7)
#速度 利用率 可读性 复杂度
# bbb=lambda a,b=2:a*b
# def a(a,b):
# print(a*b)
# a(2,2)
# def demo(n):
# return n*2
# print(demo(demo(demo(1))))
# a='123'
# def f():
# global a
# a='12'
# print(a)
# print(a)
# f()
# global nonlocal
# count=12
# def add():
# count=1
# def fun():
# nonlocal count
# print(count)
# count+=2
# return fun
# a=add()
# a()
# a()
def f1():
x=5
y=6
print(x+y)
def f2():
y=1
print(x+y)
f1()
f2()
# def a(n):
# if n==1:
# return 1
# else:
# return a(n-1)+n
# print(a(1000))
ans=0
def fu(a,b,x=1):
if b==1:
return 6
global ans
ans+=fu(a-x,b-1,2)
return ans
print(fu(5,74,3))
\ No newline at end of file
# #如何将字符串倒叙输出
# a=input("请输入长度小于80的一个字符串")#用input函数获取一个字符串
# #字符串转化列表,列表转化为字符串
# list=[] #建立一个空的列表,
# for i in a:#循环遍历字符串a
# list.insert(0,i) #将a中的每个小字符添加到列表的第一个位置,返回一个倒叙的列表
# newa=''.join(list)#用join函数将列表抓换为字符串
# print(newa)#打印出新的字符串
# #2,
# a=input("请输入长度小于80的一个字符串")
# newa='' #创建一个空的字符串
# for i in a:#循环遍历a
# newa=i+newa
# print(newa)
# a=['beijing','shanghai','huzhou','acc']
# f=open("city.csv",'a')
# f.write(','.join(a))
# f.close()
# a=[
# ['张三','98','123','124'],
# ['李四','98','123','124'],
# ['王五','98','123','124']
# ]
# f=open('cj.csv','w')
# for i in a:
# f.write(",".join(i)+'\n')
# f.close()
# f=open('cj.csv','r')
# c=[]
# for i in f:
# c.append(i.strip("\n").split(','))
# f.close()
# print(c)
# with open('123.csv','w',newline='') as f:
# a=csv.writer(f)
# a.writerow(['color','red'])
# try:
# a=int("输入一个整数")
# b=int("输入一个整数")
# m=a/b
# print('商是:',m)
# except ValueError:
# print("输入的不是数字")
# except ZeroDivisionError:
# print('除数为0')
# except:
# print('其他错位')
# finally:
# print('程序结束')
# a=[1,3,2,5,8,7,6,0]
# for i in range(len(a)-1):
# for j in range(len(a)-1):
# if a[j]>a[j+1]:
# a[j],a[j+1]=a[j+1],a[j]
# print(a)
A = [64,25,0,22,1]
for i in range(len(A)): #循环的次数
min_idx = i #自定义最小的是哪个数据的索引
for j in range(i+1,len(A)): #让其跟后面的数据进行比较
if A[min_idx] > A[j]: #如果最小的数不是min_idx,就改成j。
min_idx = j
A[i], A[min_idx] = A[min_idx], A[i]
print(A)
\ No newline at end of file
# # print(bin(1238))
# # print(eval('9.9'))
# # a=[4,1,34,2,412,41,24]
# # for i,j in enumerate(a):
# # print(i,j)
# all() 全是真就是真,否则假 all([]) all(())
# any() 全是假就是假,否则真 any([]) any(())
# a.split("")
# b=''.join(a)
# try 尝试执行这个代码
# except
# else:
# finally
# a=[23,235,1,5,4,23,5,1,0]
# for i in range(len(a)):
# for j in range(len(a)-1-i):
# if a[j]>a[j+1]:
# a[j],a[j+1]=a[j+1],a[j]
# print(a)
# print(hex(100))
\ No newline at end of file
,98,123,124
,98,123,124
,98,123,124
import csv int('5')
str(5)
print(5)
a=input("你是谁")
b=1
import turtle
forward(100)
pen.hideturtle()
turtle.done()
penup()
pendown()
pen.color('red')
pen.fillcolor('red')
pen.begin_fill()
pen.end_fill()
pen.shape('turtle')
pen.circle(50)
pen.dot(100)
bgcolor("yellow")
clear()
data = [["姓名", "语文", "数学", "英语"],
["小贝", 98, 99, 92],
["聪聪", 95, 91, 95]]
\ No newline at end of file
Markdown is supported
0% or
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or sign in to comment