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binary_search.py

 # 使用二分查找法，找出9和20在列表里面的索引
-num_list = [1, 3, 5, 8, 11, 15, 17, 18, 20, 21]
\ No newline at end of file
+num_list = [1, 3, 5, 8, 11, 15, 17, 18, 20, 21]
+num1=20
+mi=0
+mx=len(num_list)-1
+
+while mi<mx:
+    mid=(mi+mx)//2
+    gis=num_list[mid]
+    if num1==gis:
+        print("zhaodaol"+str(mid))
+    elif num1>gis:
+        mid=mid+1
+    else:
+        mid=mid-1
+
+
+