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binary_search.py

 # 使用二分查找法，找出9和20在列表里面的索引
-num_list = [1, 3, 5, 8, 11, 15, 17, 18, 20, 21]
\ No newline at end of file
+a= [1, 3, 5, 8, 11, 15, 17, 18, 20, 21]
+num=20
+high=len(a)-1
+low=0
+
+while high>=low:
+    mid=(low+high)//2
+    if a[mid]==num:
+        print(num,"的索引为：",mid)
+        break
+    if a[mid]<num:
+        low= mid+1
+    else:
+        high= mid-1
+
+