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Commit
d656113f
authored
Apr 18, 2021
by
BellCodeEditor
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递归1.py
递归1.py
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d656113f
# 1、定义一个递归函数,函数名自取;
# 1、定义一个递归函数,函数名自取;
# 2、能够接收一个num的整数参数
# 3、函数能计算1+2+3+4....num的结果
# 如果定义的函数为func(num),那么func(num)=num + func(num-1);
# 当num等于1的时候,func(1)返回值为1
def
sum_number
(
num
):
if
num
==
1
:
return
1
p
=
sum_number
(
num
-
1
)
return
num
+
p
result
=
sum_number
(
100
)
print
(
result
)
\ No newline at end of file
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