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diy1.py

+#使用递归知识，计算1+2+3+4+...一直到num的和
+def sum_numbers(num):
+    #递归的出口
+    if num == 1:
+        return 1
+    #累加和
+    n = sum_numbers(num-1)
+    return n + num 
+result = sum_numbers(100)
+print(result)
+
+# def for_sum(n):
+#     sum = 0
+#     for i in range(1,n+1):
+#         sum += i
+#     return sum
+# result = for_sum(100)
+# print(result)