auto save

diy.py

+#自己输入n个整数，然后进行从大到小排序
+
+list = []
+#input输入的是字符串类型
+n = int(input('输入排序元素的个数：'))
+
+for i in range(n):
+    list.append(int(input('输入一个整数，按回车继续：')))
+
+print('排序前的列表：',list)
+

diy1.py

+#time模块
+#time.time()
+#返回一个时间戳，秒数
+import time
+
+start_time = time.time()
+
+for a in range(0,1001):
+    for b in range(0,1001):
+        c = 1000 - a - b
+        if a**2 + b**2 == c**2:
+            print('a,b,c三个数分别为',a,b,c)
+end_time = time.time()
+
+result = end_time - start_time
+
+print('计算总消耗时间为：',result)
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diy2.py

+#冒泡排序：从小到大，从大到小
+#重复比较两个相邻元素
+#排序n-1轮
+
+
 alist = [88, 75, 72, 82, 90, 85, 78, 91]
 alist = [88, 75, 72, 82, 90, 85, 78, 91]
+
+n = len(alist)
+
+for i in range(0,n-1):  #排序n-1轮
+    for j in range(0,n-1):  #遍历列表元素下标
+        if alist[j] > alist[j+1]:
+            alist[j],alist[j+1] = alist[j+1],alist[j]
+    print(alist)

diy3.py

+import time
+
+start_time = time.time()
+
+list1 = []
+for a in range(0, 1000):
+    for b in range(0, 1000):
+        list1.append(0)
+
+end_time = time.time()
+
+result = end_time - start_time
+
+print('计算总消耗时间为：',result)
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