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Commit
0da9940a
authored
Apr 18, 2021
by
BellCodeEditor
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a99520da
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3 deletions
diy2.py
diy2.py
View file @
0da9940a
i
=
0
i
=
3
username
=
"python"
# 保存在服务器数据库中的用户账号(正确的账号)
userpassword
=
"123456"
# 保存在服务器数据库中的用户密码(正确的密码)
while
True
:
if
i
<
3
:
if
i
!=
0
:
name
=
input
(
"请输入用户名"
)
password
=
input
(
"请输入密码"
)
...
...
@@ -12,10 +12,12 @@ while True:
break
elif
username
!=
name
:
print
(
"用户名不存在,请重新输入"
)
i
=
i
+
1
i
=
i
-
1
print
(
"你还有"
+
str
(
i
)
+
"次机会"
)
continue
else
:
print
(
"密码错误"
)
print
(
"你还有"
+
str
(
i
)
+
"次机会"
)
else
:
print
(
"你的账户被锁订情凭身份证到我司解锁"
)
exit
()
...
...
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