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diy3.py

+#     啤酒2块钱一瓶
+#     4个瓶盖换一瓶
+#     2个空瓶换一瓶
+#     问：10块钱最多可以喝几瓶？
+a = 10
+g = 0
+k = 0
+number = 0
+while True:
+    if a == 0 :
+        break
+    a -= 2
+    number += 1
+    g += 1
+    k += 1
+    if k == 2:
+        number +=1
+        k = 0
+        k +=1
+        g +=1
+    if g == 4:
+        number +=1
+        g =0
+        k +=1
+        g +=1
+print(number)
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