Commit 9f2fc858 by BellCodeEditor

auto save

parent 3d5aa2a1
Showing with 42 additions and 14 deletions
# 持家小能手 (利用自动更新成绩程序的逻辑完成这个新项目) import random
# 如果输入的水果价钱比字典中的低,则替换掉,反之则不更新
cost= {'苹果':5.2,'山竹':12.9,'香蕉':2.4,'荔枝':15,'葡萄':9.3,'桂圆':8,'蓝莓':10,'李子':8} # 私钥
k=input('请输入水果名称:') key = "abcdefgh使用python实现简单的位移替换加密,制作密码机关真是太好玩了哈哈哈!"
v=input('请输入水果价钱:') # 要加密语句
# ?补充条件判断: message = "诺依,周末一起去看动漫展吧!"
if # ?: # 最终加密后的语句
# ?更新价钱 key_message = ""
print(k+'降价了,现价'+v+'元') # 干扰字符
else: noise = "port:@#$%^&"
print(k+'涨价了,我们不买') for i in message:
else: str1 = i
cost[k] = float(v) str2 = random.choice(key)
print(k+'的价钱'+v+'元已上传~') str3 = random.choice(key)
text = str1+str2+str3
key_message = key_message + text
list_message = list(key_message)
index = random.randint(0, len(key_message))
list_message.insert(index, noise)
result_message = "".join(list_message)
print(result_message)
#解密
list_message = list(result_message)
for i in range(len(noise)):
list_message.pop(index)
key_message = "".join(list_message)
print(key_message)
res = key_message[0]
i = 0
# for i in range(len(key_message)):
while i < len(key_message):
i+=3
if i <len(key_message):
res+=key_message[i]
print(res)
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