Commit aa1d84bf by BellCodeEditor

auto save

parent 98f24605
Showing with 67 additions and 1 deletions
dict_hero={'猴三':10,'猴一':21,'猴五':22,'猴队长':29,'猴七':30}
dict_hero['猴三']=15
print(dict_hero)
dict_xiyou = {}
dict_xiyou["师傅"]='唐三藏'
dict_xiyou["大师兄"]='孙悟空'
dict_xiyou["二师兄"]='猪八戒'
dict_xiyou["三师兄"]='沙师弟'
print(dict_xiyou)
if "师傅" in dict_xiyou:
print()
...@@ -9,5 +9,5 @@ for i in range(len(list_hero)): ...@@ -9,5 +9,5 @@ for i in range(len(list_hero)):
break break
print(list_hero) print(list_hero)
# 请注释掉上面的代码,并在下一行创建一个名为dict_hero的字典 # 请注释掉上面的代码,并在下一行创建一个名为dict_hero的字典
dict_hero= dict_hero={'猴三':10,'猴一':21,'猴五':22,'猴队长':29,'猴七':30}
print(dict_hero) print(dict_hero)
# 神奇百货中的物品已经帮你创建好啦,接下来要看你的了~
# dict= {'可口可乐':3,'旺仔牛奶':4,'农夫山泉':1,'辣条':3,'巴西烤肉':2,'果冻':4,'乐事':5,'奥利奥':10,'巧克力':6}
# k=input("请输入您想要的商品")
# sum=10
# s=input("请输入想要的个数:")
# if k in dict:
# if (sum-int(s))>0:
# print("您选择的"+k+"商品需要"+str(dict[k]*int(s))+"元")
# sum=sum-int(s)
# else:
# print("数量不足")
# else:
# print("此商品缺货")
# 持家小能手 (利用自动更新成绩程序的逻辑完成这个新项目)
# 如果输入的水果价钱比字典中的低,则替换掉,反之则不更新
cost= {'苹果':5.2,'山竹':12.9,'香蕉':2.4,'荔枝':15,'葡萄':9.3,'桂圆':8,'蓝莓':10,'李子':8}
k=input('请输入水果名称:')
v=input('请输入水果价钱:')
#查看水果是否在字典中
if k in cost:# ?补充条件判断:
if int(v)<cost[k]:# 如果新的价钱大于原来的价钱:
cost[k]=float(v)# ?更新价钱
print(k+'降价了,现价'+v+'元')
else:
print(k+'涨价了,我们不买')
else:
cost[k] = float(v)
print(k+'的价钱'+v+'元已上传~')
print(cost)
Markdown is supported
0% or
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or sign in to comment