Commit 44df3932 by BellCodeEditor

auto save

parent 98f24605
Showing with 149 additions and 18 deletions
# 这是悟空为花果山小猴做臂力测试的程序代码
name=input('你叫啥名啊?')
power=int(input('你臂力多少啊?'))
list_hero=['猴三',10,'猴一',21,'猴五',22,'猴队长',29,'猴七',30]
for i in range(len(list_hero)):
if i%2==1 and list_hero[i]>=power:
list_hero.insert(i-1,name)
list_hero.insert(i,power)
break
print(list_hero)
# 请注释掉上面的代码,并在下一行创建一个名为dict_hero的字典
dict_hero=
dict_hero = {'猴一':10,'猴三':20,'猴队长':29,'猴七':15}
print(dict_hero)
#提取猴队长的臂力值
a = dict_hero['猴队长']
print(a)
#修改猴队长的臂力值为32
dict_hero['猴队长'] = 32
a = dict_hero['猴队长']
print(a)
dict_hero['猴王'] = 100
print(dict_hero)
\ No newline at end of file
import time #导入时间模块
import turtle #导入时间模块
screen = turtle.Screen() #创建窗口对象
screen.bgcolor('bisque') #设置背景颜色
mouse = turtle.Turtle() #创建老鼠画笔对象
mouse.shape("turtle") #设置画笔形状为turtle
mouse.color("blue") #设置老鼠画笔颜色
cat = turtle.Turtle() #创建猫画笔对象
cat.shape("turtle") #设置猫画笔的形状为turtle
cat.color('red') #设置猫画笔颜色
mouse.up() #老鼠画笔抬笔,不会出现移动轨迹
mouse.goto(100,100) #老鼠初始位置
boxsize = 400 #设置追逐范围
caught = False #设置追逐是否成功,默认为False表示没有追逐成功
score = 0 #初始化分数为0
#创建老鼠画笔前后左右方法
def up(): #前进
mouse.fd(10)
def back(): #后退
mouse.bk(10)
def left(): #左转
mouse.lt(5)
def right(): #右转
mouse.rt(5)
def quitTurtle(): #结束游戏方法
screen.bye()
#检测老鼠是否超出追逐范围
def checkbound():
global boxsize #将变量设置为全局变量
if mouse.xcor() > boxsize: #老鼠x坐标大于追逐范围边长
mouse.goto(boxsize,mouse.ycor()) #将老鼠位置限制在右边缘
if mouse.xcor() < -boxsize:
mouse.goto(-boxsize,mouse.ycor()) #将老鼠位置限制在左边缘
if mouse.ycor() > boxsize:
mouse.goto(mouse.xcor(),boxsize) #将老鼠位置限制在上边缘
if mouse.ycor() < -boxsize:
mouse.goto(mouse.xcor(),-boxsize) #将老鼠位置限制在下边缘
#按键侦测控制老鼠前后左右移动
screen.onkeypress(up,"Up")
screen.onkeypress(back,'Down')
screen.onkeypress(left,"Left")
screen.onkeypress(right,"Right")
screen.onkeypress(quitTurtle,"Escape")
#设置游戏难度
difficulty = screen.numinput("难度","请输入游戏难度值(1~5)",minval = 1,maxval = 5)
screen.listen() #按键监听
#实现小猫画笔追逐
while not caught: #当没有追逐成功的时候才可以进行重复执行
checkbound()
cat.setheading(cat.towards(mouse)) #小猫从始至终朝向老鼠的方向
cat.forward(8 + difficulty) #小猫移动速度随着难度数值的增加而增加
score += 1 #加分
if cat.distance(mouse) < 5: #如果小猫距离老鼠的距离小于5
caught = True #将追逐状态修改为真,表示追逐成功
time.sleep(0.2-(0.01*difficulty)) #游戏运行速度随着难度提升
screen.textinput("GameOver","游戏得分:"+str(score * difficulty)) #显示最终得分
turtle.mainloop()
\ No newline at end of file
# 直接运行以下代码,说说你的发现:
list_hero=['赵一',30,'丁二',37,'孙五',52,'王猛',89,'周亮',98]
dict_hero = {'赵一':30,'丁二':37,'孙五':52,'王猛':89,'周亮':98}
print(len(list_hero))
print(len(dict_hero))
\ No newline at end of file
from turtle import * #导入turtle模块
import time #导入时间模块
window = Screen() #创建窗口对象
window.bgcolor('wheat')
mouse = Turtle() #创建老鼠画笔
mouse.color('blue') #设置老鼠画笔颜色为蓝色
cat = Turtle() #创建猫画笔对象
cat.color('red') #设置猫画笔颜色
mouse.shape("turtle") #设置画笔形状
cat.shape("turtle")
mouse.up() #老鼠画笔抬笔
mouse.goto(100,100)
boxsize = 400 #追逐范围边长
caught = False #追逐是否成功,默认为False,表示不成功
score = 0
#接下来创建老鼠画笔的前后左右方法
def up(): #上
mouse.fd(10)
def down(): #下
mouse.bk(10)
def left(): #左
mouse.lt(10)
def right(): #右
mouse.rt(10)
def quit():
window.bye() #关闭游戏窗口
#创建侦测是否超出范围的方法
def checkbound():
global boxsize #转为全局变量
if mouse.xcor() > boxsize:
mouse.goto(boxsize,mouse.ycor())
if mouse.xcor() < -boxsize:
mouse.goto(-boxsize,mouse.ycor())
if mouse.ycor() > boxsize:
mouse.goto(mouse.xcor(),boxsize)
if mouse.ycor() < -boxsize:
mouse.goto(mouse.xcor(),-boxsize)
#按键控制老鼠移动
window.onkeypress(up,"Up")
window.onkeypress(down,"Down")
window.onkeypress(left,"Left")
window.onkeypress(right,"Right")
window.onkeypress(quit,"Escape")
lv = window.numinput("难度","请输入难度值(1~5)",minval = 1,maxval = 5)
window.listen() #窗口监听
#小猫画笔的移动
while not caught: #没有追逐成功的时候才可以进行重复执行
checkbound()
cat.setheading(cat.towards(mouse)) #让小猫始终朝向老鼠的方向
cat.fd(2 + lv) # 小猫移速随着难度提升而增加
score += 1
if cat.distance(mouse) < 5: #如果猫与老鼠的距离小于5
caught = True
time.sleep(0.2-(0.01*lv)) #控制游戏运行速度,难度越高,速度越快
window.textinput("GameOver","游戏得分:"+str(score * lv))
mainloop() #保持监听(窗口不关闭)A
\ No newline at end of file
Markdown is supported
0% or
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or sign in to comment