Commit df7a8d62 by BellCodeEditor

save project

parent bdda37ef
Showing with 8 additions and 19 deletions
# 古代测量臂力是靠不同重量的石锁,只能测整数哦。
# 最小的石锁是30公斤最大的石锁是100公斤,注意输入的数字哦。
# 请优化刚刚的代码,并增添交互效果,和自动输出最强三人信息的功能~
# 问询处
name = input("姓名:")
power = int(input("臂力:"))
# 归档处
hero=['赵一',30,'丁二',37,'孙五',52,'王猛',89,'周亮',98,'张宇',100]
for i in range(len(hero)):
if i%2 == 1 and hero[i]>=power:
hero.insert(i-1,name)
hero.insert(i,power)
break
print(hero[len(hero)-6:len(hero)+1])
# 打印出臂力最强的三个人和他们对应的臂力值:
students = ['悟空','小贝','八戒','波奇']
students.pop(2)
students.extend("诺依")
red = students=['悟空','小贝']
blue = students=['八戒','波奇']
print(red)
print(blue)
\ No newline at end of file
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