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diy.py

@@ -3,12 +3,27 @@
 # 请优化刚刚的代码，并增添交互效果，和自动输出最强三人信息的功能~
 # 请优化刚刚的代码，并增添交互效果，和自动输出最强三人信息的功能~
 
 
 # 问询处
 # 问询处
-
-
+name = input("what's your name?\n")
+power = int(input("how much about your power?\n"))
+a = []
 # 归档处
 # 归档处
 hero=['赵一',30,'丁二',37,'孙五',52,'王猛',89,'周亮',98,'张宇',100]
 hero=['赵一',30,'丁二',37,'孙五',52,'王猛',89,'周亮',98,'张宇',100]
 for i in range(len(hero)):
 for i in range(len(hero)):
-
+    print(i)
+    if i % 2 == 1:
+        if i - len(hero)-1 == 0:
+            print(i)
+            if hero[i]<power:
+                a.append(hero[i-1])
+                a.append(hero[i])
+            else:
+                print(123456)
+        else:
+            
+            a.append(name)
+            a.append(power)
+print(a)
+print("The men's name who has biggest power is"+"\n"+a[len(a)-2])
 
 
 
 
 
 

diy1.py

+# 古代测量臂力是靠不同重量的石锁，只能测整数哦。
+# 最小的石锁是30公斤最大的石锁是100公斤，注意输入的数字哦。
+# 请优化刚刚的代码，并增添交互效果，和自动输出最强三人信息的功能~
+
+# 问询处
+name = input("what's your name?\n")
+power = int(input("how much about your power?\n"))
+a = []
+# 归档处
+hero=['赵一',30,'丁二',37,'孙五',52,'王猛',89,'周亮',98,'张宇',100]
+for i in range(len(hero)):
+    if i % 2 == 1 and hero[i]>power:
+        hero.insert(i-1,name)
+        hero.insert(i,power)
+        break
+print("The men's name who has biggest power is"+"\n"+str(hero[-6:]))
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