auto save

1.py

+cnt = 0#count the sum of reault
+for i in range(1,5):
+    for j in range(1,5):
+        for k in range(1,5):
+            if i!=j and i!=k and j!=k 
+                print i*100+j*10+k 
+                cnt+=1
+print cnt
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2.py

+i = int(raw_input('Enter the profit:'))
+arr = [1000000,600000,400000,200000,100000,0]
+rat = [0.01,0.015,0.03,0.05,0.075,0.1]
+r = 0
+for idx in range(0,6):
+    if i>arr[idx]:
+        r+=(i-arr[idx])*rat[idx]
+        print (i-arr[idx])*rat[idx]
+        i=arr[idx]
+print r
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3.py

+import datetime 
+import time
+dtstr =str(raw_input('Enter the datetime:(20151215):'))
+dt = datetime.datetime.strptime(dtstr,"%Y%m%d")
+another dtstr = dtstr[:4] + '0101'
+another dt = datetime.datetime.strptime(another dtstr,"%Y%m%d")
+print(int((dt-another_dt).days) + 1
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diy.py

-# 古代测量臂力是靠不同重量的石锁，只能测整数哦。
-# 最小的石锁是30公斤最大的石锁是100公斤，注意输入的数字哦。
-# 请优化刚刚的代码，并增添交互效果，和自动输出最强三人信息的功能~
 
-# 问询处
-power=input("你的臂力值是:")
-name=input("你的名字:")
-# 归档处
-hero=['赵一',30,'丁二',37,'孙五',52,'王猛',89,'周亮',98,'张宇',100]
-for i in range(len(hero)):
-    if i%2==1 and hero[i]>=int(power):
-        hero.insert(i-1,name)
-        hero.insert(i,power)
+import math
+num = 1
+while True:
+    if math.sqrt(num + 100)-int(math.sqrt(num + 100))==0 and math.sqrt(num + 268)-int(math.sqrt(num + 268))==0:
+        print(num)
         break
-print(hero[-6:])
-# 打印出臂力最强的三个人和他们对应的臂力值：
+    num += 1
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