Commit 5e8d7d5d by BellCodeEditor

save project

parent c50ffccc
Showing with 14 additions and 16 deletions
# 古代测量臂力是靠不同重量的石锁,只能测整数哦。
# 最小的石锁是30公斤最大的石锁是100公斤,注意输入的数字哦。
# 请优化刚刚的代码,并增添交互效果,和自动输出最强三人信息的功能~
hero=['赵一',30,'丁二',37,'孙五',52,'王猛',89,'周亮',98,'张宇',100]
# 问询处
name=input("姓名?")
power=input("臂力大小?")
while True:
def da_yin():
name=input("姓名?")
power=input("臂力大小?")
if int(power)<30 or int(power)>100:
power=input("请重新输入臂力大小?")
else:
break
# 归档处
hero=['赵一',30,'丁二',37,'孙五',52,'王猛',89,'周亮',98,'张宇',100]
for i in range(len(hero)):
if i%2==1 and hero[i]>=int(power):
hero.insert(i-1,name)
hero.insert(i,int(power))
break
# 打印出臂力最强的三个人和他们对应的臂力值:
print(hero[-6:])
\ No newline at end of file
for i in range(len(hero)):
if i%2==1 and hero[i]>=int(power):
hero.insert(i-1,name)
hero.insert(i,int(power))
break
print(hero[-6:])
while True:
da_yin()
\ No newline at end of file
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