Commit 473e586e by BellCodeEditor

save project

parent 1c3a38d0
Showing with 6 additions and 15 deletions
# 古代测量臂力是靠不同重量的石锁,只能测整数哦。
# 最小的石锁是30公斤最大的石锁是100公斤,注意输入的数字哦。
# 请优化刚刚的代码,并增添交互效果,和自动输出最强三人信息的功能~
# 问询处
# 归档处
hero=['赵一',30,'丁二',37,'孙五',52,'王猛',89,'周亮',98,'张宇',100]
for i in range(len(hero)):
# 打印出臂力最强的三个人和他们对应的臂力值:
hero=['赵一','丁二','孙五','王猛','周亮']
hero.append('张宇')
hero.append('周亮')
print(hero)
hero.count('周亮')
print(hero.count('周亮'))
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