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lesson6-5-2
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Commit
384ce12a
authored
7 months ago
by
BellCodeEditor
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diy.py
diy.py
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384ce12a
#
古代测量臂力是靠不同重量的石锁,只能测整数哦。
#
最小的石锁是30公斤最大的石锁是100公斤,注意输入的数字哦。
#
请优化刚刚的代码,并增添交互效果,和自动输出最强三人信息的功能~
#
#任务1:运用切片在列表中取出刘备关羽张飞
#
a=["袁术","刘备","关羽","张飞","曹操"]
#
print(a[1:4])
# 问询处
# #任务2:运用切片在列表中取出刘备关羽张飞,加入到列表b中。
# b=["吕布"]
# c=["袁术","颜良","刘备","关羽","张飞","曹操","文丑"]
# b.extend(c[2:5])
# print(b)
# 归档处
hero
=
[
'赵一'
,
30
,
'丁二'
,
37
,
'孙五'
,
52
,
'王猛'
,
89
,
'周亮'
,
98
,
'张宇'
,
100
]
# #任务3:将赵四的臂力值加入到列表hero中,并排序
name
=
"赵四"
power
=
78
hero
=
[
"袁一"
,
50
,
"张二"
,
65
,
"刘三"
,
75
,
"杨六"
,
88
,
"黄五"
,
99
]
#对hero列表进行遍历
for
i
in
range
(
len
(
hero
)):
if
i
%
2
==
1
and
hero
[
i
]
>=
power
:
#判断power的大小
hero
.
insert
(
i
-
1
,
name
)
hero
.
insert
(
i
,
power
)
break
print
(
hero
)
#插入到列表中
# 打印出臂力最强的三个人和他们对应的臂力值:
#显示结果
\ No newline at end of file
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