Commit 2c04d592 by BellCodeEditor

save project

parent b811f3f2
Showing with 17 additions and 0 deletions
# 古代测量臂力是靠不同重量的石锁,只能测整数哦。
# 最小的石锁是30公斤最大的石锁是100公斤,注意输入的数字哦。
# 请优化刚刚的代码,并增添交互效果,和自动输出最强三人信息的功能~
# 问询处
name=input("你叫啥名啊?")
power=int(input("你臂力多少啊?"))
# 归档处
hero=['赵一',30,'丁二',37,'孙五',52,'王猛',89,'周亮',98,'张宇',100]
for i in range(len(hero)):
if i%2==1 and hero[i]>=power:
hero.insert(i-1,name)
hero.insert(i,power)
break
print(hero[8:14])
++ "b/\343\200\202py"
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