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lesson10-2
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fa8ae52f
authored
Jan 22, 2020
by
Administrator
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diy1.py
diy1.py
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fa8ae52f
# 灭霸打了一个响指,宇宙一半生物都灰飞烟灭。
# 剩下的复仇者联盟成员们依旧没有放弃反击灭霸的机会,他们决定利用最后一次行动机会,去把灭霸手里的宝石偷回来。
# 如果偷回的宝石数是4颗及以上,便获得了打败灭霸的力量;如果偷回的宝石数是1-3颗,他们可以全员出动,殊死一搏;如果偷回的宝石数是0颗,只能尝试呼叫惊奇队长。
# 最终,他们因为实力相差太大,1颗宝石都没有偷回来。
# 悟空读了上面的故事,写出一段代码,在一颗宝石都没偷回来的赋值下,进行条件判断,并产生对应的结果:
# 如果偷回的宝石数是4颗及以上,输出结果:获得了打败灭霸的力量,反杀稳了
# 如果偷回的宝石数是1-3颗,输出结果:可以全员出动,殊死一搏
# 如果偷回的宝石数是0颗,输出结果:没办法了,只能尝试呼叫惊奇队长
# 但是运行错误了,请你帮助悟空消灭bug!
if
stonenumber
>=
4
:
print
(
'获得了打败灭霸的力量,反杀稳了'
)
elif
1
<=
stonenum
<=
3
:
print
(
'可以全员出动,殊死一搏'
)
else
:
print
(
'没办法了,只能尝试呼叫惊奇队长'
)
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